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pinaiev1997
@pinaiev1997
October 2021
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решите двойные неравенства 2<4x+3днлёное на три≤3
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ewgenijbark
Verified answer
[tex]2< \frac{4x+3}{3} \leq 3 \\ 6<4x+3 \leq 9 \\ 3<4x \leq 6 \\ \frac{3}{4}<x \leq \frac{6}{4} \\ 0.75<x \leq 1.5 [tex]
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Rechnung
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2< (4x+3)/3 ≤3
2*3 < 4x+3 ≤3*3
6 < 4x+3 ≤ 9
6-3 < 4x ≤ 9-3
3 < 4x ≤ 6
3/4 < x ≤ 6/4
0,75 < x ≤1,5
x∈(0,75;1,5]
0 votes
Thanks 0
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Answers & Comments
Verified answer
[tex]2< \frac{4x+3}{3} \leq 3 \\ 6<4x+3 \leq 9 \\ 3<4x \leq 6 \\ \frac{3}{4}<x \leq \frac{6}{4} \\ 0.75<x \leq 1.5 [tex]|||
Verified answer
2< (4x+3)/3 ≤32*3 < 4x+3 ≤3*3
6 < 4x+3 ≤ 9
6-3 < 4x ≤ 9-3
3 < 4x ≤ 6
3/4 < x ≤ 6/4
0,75 < x ≤1,5
x∈(0,75;1,5]