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arch123
@arch123
July 2022
1
12
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решите эти уравнения по теореме Виета
1)x^2+20x+99=0
2)x^2+9x+14=0
3)x^2+10x+24=0
4)x^2-x-6=0
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alkalmykova68
1) x^2+20x+99=0 (a=1,b=20,c=99)
x1+x2=-20 (числу b с противоположным знаком)
x1*x2=99
x1=-11; x2=-9
2)
x^2+9x+14=0
x1+x2=-9
x1*x2=14
x1=-7 x2=-2
3)x^2+10x+24=0
x1+x2=-10
x1*x2=24
x1=-6 x2=-4
4)x^2-x-6=0
x1=3 x2=-2
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Answers & Comments
x1+x2=-20 (числу b с противоположным знаком)
x1*x2=99
x1=-11; x2=-9
2) x^2+9x+14=0
x1+x2=-9
x1*x2=14
x1=-7 x2=-2
3)x^2+10x+24=0
x1+x2=-10
x1*x2=24
x1=-6 x2=-4
4)x^2-x-6=0
x1=3 x2=-2