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meowvirt
@meowvirt
August 2022
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Решите геометрию, пожалуйста.
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zmeura1204
Ответ:
S(ABCD)=21√10
Решение:
S(∆ABD)=√(p(p-AB)(p-BD)(p-AD));
p=(AB+BD+AD)/2=(7+11+12)/2=30/2=15
S(∆ABD)=√(15(15-7)(15-11)(15-12))=
=√(15*8*4*3)=√1440=12√10;
S(∆ABD)=½*BH*AD;
BH=2*S(∆ABD)/AD=2*12√10/12=
=2√10.
S(ABCD)=BH(BC+AD)/2=
=2√10*(9+12)/2=√10*21=21√10
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Answers & Comments
S(ABCD)=21√10
Решение:
S(∆ABD)=√(p(p-AB)(p-BD)(p-AD));
p=(AB+BD+AD)/2=(7+11+12)/2=30/2=15
S(∆ABD)=√(15(15-7)(15-11)(15-12))=
=√(15*8*4*3)=√1440=12√10;
S(∆ABD)=½*BH*AD;
BH=2*S(∆ABD)/AD=2*12√10/12=
=2√10.
S(ABCD)=BH(BC+AD)/2=
=2√10*(9+12)/2=√10*21=21√10