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NezamedinovRuslan
@NezamedinovRuslan
July 2022
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Решите хоть 1-ин и лучше сфоткайте решение <3
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sedinalana
[(a²+3)/2a]²-3a=(a²+3)²/4a²-3=(a^4+6a²+9-12a²)/4a²=(a^4-6a²+9)/4a²=
=[(a²-3)/2a]²
√[(a²-3)/2a]²=|(a²-3)/2a|
(a²-3):|a²-3|/|2a|=|2a|*(a²-3)/|a²-3|
1)a<-√3
-2a(a²-3)/(a²-3)=-2a
2)-√3<a<0
-2a*(a²-3)/(3-a²)=2a
3)0<a<√3
2a(a²-3)/(3-a²)=-2a
4)a>√3
2a(a²-3)/(a²-3)=2a
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Answers & Comments
=[(a²-3)/2a]²
√[(a²-3)/2a]²=|(a²-3)/2a|
(a²-3):|a²-3|/|2a|=|2a|*(a²-3)/|a²-3|
1)a<-√3
-2a(a²-3)/(a²-3)=-2a
2)-√3<a<0
-2a*(a²-3)/(3-a²)=2a
3)0<a<√3
2a(a²-3)/(3-a²)=-2a
4)a>√3
2a(a²-3)/(a²-3)=2a