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мистерфриз
@мистерфриз
July 2022
1
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решите Икс вторых плюс Икс 3 _=10{про икс там в дробях обычных}
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lightning2000
X\2 +x\3 = 10
(3X+2x)\6=10
5x\6=10
5x=10*6
5x=60
x=60\5
x=12
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Answers & Comments
(3X+2x)\6=10
5x\6=10
5x=10*6
5x=60
x=60\5
x=12