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tyshenko9812
@tyshenko9812
June 2022
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Решите иррациональное уравнение
√1+8x+2x=x+3
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krugly1981
√1 + 8x + 2x² = x + 3
2x² + 8x + 1 = (x + 3)²
2x² + 8x + 1 = x² + 6x + 9
2x² - x² + 8x - 6x + 1 - 9 = 0
x² + 2x - 8 = 0
D = b² - 4ac = 4 - 4 × ( - 8) = 4 + 32 = 36 = 6²
x1 = ( - 2 + 6) / 2 = 2
x2 = ( - 2 - 6) / 2 = - 4
Ответ: x1 = 2, x2 = - 4.
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Thanks 1
tyshenko9812
спасибо огромное
krugly1981
пожалуйста,успехов!
tyshenko9812
сможете мне еще помочь?
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Answers & Comments
2x² + 8x + 1 = (x + 3)²
2x² + 8x + 1 = x² + 6x + 9
2x² - x² + 8x - 6x + 1 - 9 = 0
x² + 2x - 8 = 0
D = b² - 4ac = 4 - 4 × ( - 8) = 4 + 32 = 36 = 6²
x1 = ( - 2 + 6) / 2 = 2
x2 = ( - 2 - 6) / 2 = - 4
Ответ: x1 = 2, x2 = - 4.