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nikitina9911
@nikitina9911
July 2022
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решите квадратичное неравенство x^2-20x≥-11x-7-x^2
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m11m
Х²-20х≥-11х-7-х²
х²+х²-20х+11х+7≥0
2х²-9х+7≥0
f(x)=2x²-9x+7 - парабола, ветви направлены вверх
Нули функции:
2х²-9х+7=0
Д=(-9)²-4*2*7=81-56=25=5²
х₁=(9-5)/4=4/4=1
х₂=14/4=3,5
+ - +
------
1
---------
3,5
------
\\\\\\\ \\\\\\\
х∈(-∞; 1]∨[3.5; ∞)
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Answers & Comments
х²+х²-20х+11х+7≥0
2х²-9х+7≥0
f(x)=2x²-9x+7 - парабола, ветви направлены вверх
Нули функции:
2х²-9х+7=0
Д=(-9)²-4*2*7=81-56=25=5²
х₁=(9-5)/4=4/4=1
х₂=14/4=3,5
+ - +
------ 1--------- 3,5 ------
\\\\\\\ \\\\\\\
х∈(-∞; 1]∨[3.5; ∞)