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Timaveider
@Timaveider
July 2022
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Решите квадратное уравнение 4(10x−10)2−11(10x−10)+6=0.
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sedinalana
Verified answer
10x-10=a
4a²-11a+6=0
D=124-96=25
a1=(11-5)/8=3/4⇒10x-10=0,75⇒10x=10,75⇒x=1,075
a2=(11+5)/8=2⇒10x-10=2⇒10x=12⇒x=1,2
1 votes
Thanks 1
Эля145
Пусть y=10x-10
4y^2-11y+6=0
D=b^2-4ab=121-4*4*6=121-96=25
√D=5
x1= (11+5)/2*4=2
x2=(11-5)/2*4=0.75
10x-10=2
10x=12
x=12/10
x=6/5=1 1/5
10x-10=0.75
10x=10.75
x=1.075
0 votes
Thanks 0
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Answers & Comments
Verified answer
10x-10=a4a²-11a+6=0
D=124-96=25
a1=(11-5)/8=3/4⇒10x-10=0,75⇒10x=10,75⇒x=1,075
a2=(11+5)/8=2⇒10x-10=2⇒10x=12⇒x=1,2
4y^2-11y+6=0
D=b^2-4ab=121-4*4*6=121-96=25
√D=5
x1= (11+5)/2*4=2
x2=(11-5)/2*4=0.75
10x-10=2
10x=12
x=12/10
x=6/5=1 1/5
10x-10=0.75
10x=10.75
x=1.075