Ответ:

Объяснение:

2ax^2+(5b-2a)x-5b = 0

2ax^2+5bx-2ax-5b = 0

2ax*(x-1)+5b*(x-1) = 0

(2ax+5b)*(x-1) = 0

(2ax+5b)=0 => x1 = -5b/2a

(x-1) = 0 => x2 = 1