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steamgamer1
@steamgamer1
November 2021
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решите логарифмическое неравенство log2(6x-7)<log2(4x+1)
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mikael2
Log2(6x-7)<log2(4x+1) ↔
6x-7<4x+1 2x<8 x<4
6x-7>0 x>7/6
4x+1>0 x>-1/4
x∈(7/6;4)
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LenovoGungli
Приложение Photomath в помощь
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Answers & Comments
6x-7<4x+1 2x<8 x<4
6x-7>0 x>7/6
4x+1>0 x>-1/4
x∈(7/6;4)