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Sasha6674
@Sasha6674
July 2022
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Решите логорифмы, пожалуйста!
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nKrynka
1) log(6) 2 + log(6) 3 = log(6) (2*3) = 1
2) log(5)- log(5) 3 + 2^(log(2) 3 = log(5) [75/3] + 3 = log(5) 25 + 3 = 2*log(5) 5 + 3 = 2 + 3 = 8
3) log(√2) (2√3 - √8) + log(√2) (2√3 + 8) = log(√2) [(2√3)^2 - (√8)^2] =
= log(√2) [12 - 8] = log(√2) [4] = 4*log(2) 2 = 4
5) 2^(log(2) (∛7) + (1/30^(log(3) 2 = 2^(log(2)7 - 2 = 7 - 2 = 5
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Answers & Comments
2) log(5)- log(5) 3 + 2^(log(2) 3 = log(5) [75/3] + 3 = log(5) 25 + 3 = 2*log(5) 5 + 3 = 2 + 3 = 8
3) log(√2) (2√3 - √8) + log(√2) (2√3 + 8) = log(√2) [(2√3)^2 - (√8)^2] =
= log(√2) [12 - 8] = log(√2) [4] = 4*log(2) 2 = 4
5) 2^(log(2) (∛7) + (1/30^(log(3) 2 = 2^(log(2)7 - 2 = 7 - 2 = 5