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SANEATOP
@SANEATOP
July 2022
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решите на множестве R Уравнение а) х^2-4x=12 б) 4x^2+12x=16
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2407Alexa
V- корень квадратный
х^2-4х-12=0
D =(-4)^2-4*1*(-12)=16+48=64
x1=(-(-4)+V64)/2*1=(4+8)/2=12/2=6
x2=(-(-4)-V64)/2*1=(4-8)/2=-4/2=-2
По теореме Виета
х1+х2=-p=-(-4)=4
x1*x2=q=-12
x1=6
x2=-2;
4x^2+12x-16=0|:4
x^2+3x-4=0
D=3^2-4*1*(-4)=9+16=25
x1=(-3+V25)/2*1=(-3+5)/2=2/2=1
x2=(-3-V25)/2*1=(-3-5)/2=-8/2=-4
По теореме Виета
х1+х2=-p=-3
x1*x2=q=-4
x1=1
x2=-4;
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Answers & Comments
х^2-4х-12=0
D =(-4)^2-4*1*(-12)=16+48=64
x1=(-(-4)+V64)/2*1=(4+8)/2=12/2=6
x2=(-(-4)-V64)/2*1=(4-8)/2=-4/2=-2
По теореме Виета
х1+х2=-p=-(-4)=4
x1*x2=q=-12
x1=6
x2=-2;
4x^2+12x-16=0|:4
x^2+3x-4=0
D=3^2-4*1*(-4)=9+16=25
x1=(-3+V25)/2*1=(-3+5)/2=2/2=1
x2=(-3-V25)/2*1=(-3-5)/2=-8/2=-4
По теореме Виета
х1+х2=-p=-3
x1*x2=q=-4
x1=1
x2=-4;