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DoGe220
@DoGe220
March 2022
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Решите неравенства 1-3.
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Камилота2004
1. Х'2+2х-3<=0
D=4-4*3*1=16
X1x2=(-2+-4)/2
X1=1
X2=-3
2.x'2-6x>o
D=36
X1x2=(6+-6)/2
X1=6
X2=0
3.x'2-9>=0
D=36
X1x2=(0+-6)/2
X1=3
X2=-3
0 votes
Thanks 0
tamarabernukho
1)x²+2x-3≤0
x²+3x-x-3≤0
x(x+3)-(x+3)≤0
(x+3)(x-1)≤0
+++[-3]-----[1]+++
x∈[-3;1]
2)x²-6x>0
x(x-6)>0
++++(0)-----(6)+++
x∈(-∞;0)U(6;+∞)
3)x²-9≥0
(x-3)(x+3)≥0
+++[-3]-----[3]++++
x∈(-∞;-3]U[3;+∞)
0 votes
Thanks 0
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Answers & Comments
D=4-4*3*1=16
X1x2=(-2+-4)/2
X1=1
X2=-3
2.x'2-6x>o
D=36
X1x2=(6+-6)/2
X1=6
X2=0
3.x'2-9>=0
D=36
X1x2=(0+-6)/2
X1=3
X2=-3
x²+3x-x-3≤0
x(x+3)-(x+3)≤0
(x+3)(x-1)≤0
+++[-3]-----[1]+++
x∈[-3;1]
2)x²-6x>0
x(x-6)>0
++++(0)-----(6)+++
x∈(-∞;0)U(6;+∞)
3)x²-9≥0
(x-3)(x+3)≥0
+++[-3]-----[3]++++
x∈(-∞;-3]U[3;+∞)