решите неравенства:
-2x^2+10x-12<0
2x^2+2>0
x^2+2x+3<0
3x>x^2
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1)-2x^2+10x-12=0
D=(10)^2-4*(-2)*-(12)=100-96=4
x1=-10+2/4=-2
x2=-10-2/4=-3
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Verified answer
1)-2x^2+10x-12=0
D=(10)^2-4*(-2)*-(12)=100-96=4
x1=-10+2/4=-2
x2=-10-2/4=-3