Решите неравенства 3 и 4! Пожалуйста. Created by BeautyRoomy. algebra-ru

Решите неравенства 3 и 4! Пожалуйста...

BeautyRoomy @BeautyRoomy

August 2022 2 10 Report

Решите неравенства 3 и 4! Пожалуйста

irinan2014

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Решаем методом интервалов.

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sedinalana

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3
(3x-1)/(x-1)-(2x+1)/(x+1)-1<0
ОЗ (x-1)(x+1)
(3x²+3x-x-1-2x²+2x-x+1-x²+1)/(x-1)(x+1)<0
(3x+1)/(x-1)(x+1)<0
x=-1/3 x=1 x=-1
_ + _ +
------------(-1)--------------(-1/3)------------(1)------------------
x∈(-∞;-1) U (-1/3;1)
4
(2y+1)/(y+2)+(1-5y)/(y-3)+3≥0
ОЗ (y+2)(y-3)
(2y²-6y+y-3+y+2-5y²-10y+3y²-3y-18)/(y+2)(y-3)≥0
(-17y-19)/(y+2)(y-3)≥0
y=-19/17 y=-2 y=3
+ _ + _
------------------(-2)------------[-19/17]---------(3)----------------
x∈(-∞;-2) U [-19/17;3)

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Answers & Comments

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