Решите неравенства:
7(y+3)-2(y+2) ≥ =2 (5y+1)
6(3+5y)-(2+7y)= ≤ 5(4+3y)
4(3y-1)-3(y-1)>2(3+y)
7(y+3)-2(y+2) ≥ =2 (5y+1)
6(3+5y)-(2+7y)= ≤ 5(4+3y)
4(3y-1)-3(y-1)>2(3+y)
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Answers & Comments
7у-2у-10у≥2-21+4
-5у≥-15
у≤3
2)18+30у-2-7у≤20+15у
30у-7у-15у≤20-18+2
8у≤4
у≤0,5
3)12у-4-3у+3>6+2у
12у-3у-2у>6+4-3
7у>7
у>1