решите неравенства а)5(x-2)+12>7-3(x+4) b)3(a+8)-5(a-1)

xcavadova2002 @xcavadova2002

September 2021 2 23 Report

решите неравенства
а)5(x-2)+12>7-3(x+4)
b)3(a+8)-5(a-1)<7
c)4(x-1.5)+1≥6x+1.2
d)4x-(x+6)_3(2-x)≤4

NNNLLL54

Verified answer

$1)\; \; \; 5(x-2)+12\ \textgreater \ 7-3(x+4)\\\\5x-10+12\ \textgreater \ 7-3x-12\\\\8x\ \textgreater \ -7\\\\x\ \textgreater \ -\frac{7}{8}\\\\2)\; \; \; 3(a+8)-5(a-1)\ \textless \ 7\\\\3x+24-5x+5\ \textless \ 7\\\\-2x\ \textless \ -22\\\\x\ \textgreater \ 11\\\\3)\; \; 4(x-1,5)+1 \geq 6x+1,2\\\\4x-6+1 \geq 6x+1,2\\\\ -6,2\geq 2x\\\\x \leq -3,1$

$4)\; \; \; 4x-(x+6)-3(2-x) \leq 4\\\\4x-x-6-6+3x \leq 4\\\\6x \leq 16\\\\x \leq \frac{16}{6}\\\\x \leq \frac{8}{3}\\\\x \leq 2\frac{2}{3}$

1 votes Thanks 1

Fatalion 1) 5х-10+12>7-3х-12
8х>-7
х>-0.875 или 7 восьмых
2) 3a+24-5a+5<7
-2a<-26
a<13
3) 4x-6+1>6x+1.2
-2x>6.2
x>-3.1
4) 4x-x-6-6+3x<4
6x<16
x<2 целых двух третьих

2 votes Thanks 1

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