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рыбулька123
@рыбулька123
October 2021
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Решите неравенства
(Х-1)^2< √2 (х-1)
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oganesbagoyan
Verified answer
(x-1)² <√2(x-1) ;
(x-1)² - √2(x-1) < 0 ;
(x-1)(x-1- √2) < 0 ;
методом интервалов :
+ - +
------- (1) ------- (1+√2) -------
ответ : x∈(1 ; 1+√2) .
1 votes
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oganesbagoyan
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Answers & Comments
Verified answer
(x-1)² <√2(x-1) ;(x-1)² - √2(x-1) < 0 ;
(x-1)(x-1- √2) < 0 ;
методом интервалов :
+ - +
------- (1) ------- (1+√2) -------
ответ : x∈(1 ; 1+√2) .