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АнатолийРубчинский
@АнатолийРубчинский
June 2022
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решите неравенства методом интервалов б)х^2-81>0
в)х^2<1,7х
г)х(х+3)-6<3(х+1)
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m11m
Verified answer
Б)
x²-81>0
(x-9)(x+9)>0
x=9 x= -9
+ - +
-----------
-9 ------------- 9
------------
\\\\\\\\\\\\ \\\\\\\\\\\
x∈(-∞;-9)U(9; +∞)
в)
x²<1.7x
x²-1.7x<0
x(x-1.7)<0
x=0 x=1.7
+ - +
--------- 0
-----------
1.7 --------
\\\\\\\\\\\\
x∈(0; 1.7)
в)
x(x+3)-6<3(x+1)
x²+3x-6-3x-3<0
x²-9<0
(x-3)(x+3)<0
x=3 x= -3
+ - +
------- -3 ---------- 3 ---------
\\\\\\\\\\\\\
x∈(-3; 3)
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Answers & Comments
Verified answer
Б)x²-81>0
(x-9)(x+9)>0
x=9 x= -9
+ - +
----------- -9 ------------- 9 ------------
\\\\\\\\\\\\ \\\\\\\\\\\
x∈(-∞;-9)U(9; +∞)
в)
x²<1.7x
x²-1.7x<0
x(x-1.7)<0
x=0 x=1.7
+ - +
--------- 0 ----------- 1.7 --------
\\\\\\\\\\\\
x∈(0; 1.7)
в)
x(x+3)-6<3(x+1)
x²+3x-6-3x-3<0
x²-9<0
(x-3)(x+3)<0
x=3 x= -3
+ - +
------- -3 ---------- 3 ---------
\\\\\\\\\\\\\
x∈(-3; 3)