Решите неравенство: 1) 5x + 4 ≤ x + 16; 2) 4x

Ответ:1) 5x+4≤x+165x-x≤16-44x≤12x=x=32)4x-4<9x+54x-9x<5+4-5x<9x>x>1,83) 2x-3(x-7)≤32x-3x+21≤32x-3x≤3-21-x≤-18x≥18Объяснение:

cucumberrick2020 @cucumberrick2020

July 2022 1 3 Report

Решите неравенство:
1) 5x + 4 ≤ x + 16;
2) 4x – 4 < 9x + 5;
3) 2x − 3(x−7) ≤ 3.

Answers & Comments

xbdbsqhgqhixuhsgv

Ответ:

1) 5x+4≤x+16

5x-x≤16-4

4x≤12

x= $\frac{12}{4}$

x=3

2)4x-4<9x+5

4x-9x<5+4

-5x<9

x> $\frac{9}{-5}$

x>1,8

3) 2x-3(x-7)≤3

2x-3x+21≤3

2x-3x≤3-21

-x≤-18

x≥18

Объяснение:

1 votes Thanks 1

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