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DashaWayne
@DashaWayne
July 2022
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решите неравенство
28(x^2+1)≤x+30
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sedinalana
Verified answer
28x²-x-2≤0
D=1+224=225
x1=(1-15)/56=-1/4
x2=(1+15)/56=2/7
x∈[-1/4;2/7]
1 votes
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afanasevanatal
Verified answer
28(х²+1) ≤ х+30
28х² + 28 ≤ х + 30
28х²+28-х-30≤0
28х²-х-2≤0
D = 1-4*28*(-2)=1+224=225=15²
х1=1+15/56=16/56=2/7
х2=1-15/56=-14/56=-2/8=-1/4
х€[1/4;2/7]
0 votes
Thanks 0
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Answers & Comments
Verified answer
28x²-x-2≤0D=1+224=225
x1=(1-15)/56=-1/4
x2=(1+15)/56=2/7
x∈[-1/4;2/7]
Verified answer
28(х²+1) ≤ х+3028х² + 28 ≤ х + 30
28х²+28-х-30≤0
28х²-х-2≤0
D = 1-4*28*(-2)=1+224=225=15²
х1=1+15/56=16/56=2/7
х2=1-15/56=-14/56=-2/8=-1/4
х€[1/4;2/7]