решите неравенство (2х+2)^2>(x-5)^2 помогите плиз*
(2х+2)^2>(x-5)^2
4(x+1)^2>(x-5)^2
(x-1)(x+7)>0
x(x+6)>7
x>1
x<-7
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(2х+2)^2>(x-5)^2
4(x+1)^2>(x-5)^2
(x-1)(x+7)>0
x(x+6)>7
x>1
x<-7