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seriojka2002
@seriojka2002
July 2022
2
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Решите неравенство 2x^2-3x-2<=0 (см фотографию)
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erzhan9210
Verified answer
2х²-3х-2≤0
Д=3²-4*2*(-2)=9+16=25=5²
х1=(3+5)/4=2
х2=(3-5)/4=-0,5
+. - +
_____.____._____
-0,5 2
[-0,5;2]
4 votes
Thanks 8
kratgv
Verified answer
2х²-3х-2≤0
2х²-3х-2=0
Д=9-4·2·(-2)=25
√Д=5
х1=2
х2=-0,5
2х²-3х-2=2(х-2)(х+0,5)
2(х-2)(х+0,5)≤0
+ - +
---------------i----------------i--------→-
-0,5 2
x∈[-0,5;2]
1 votes
Thanks 6
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Answers & Comments
Verified answer
2х²-3х-2≤0Д=3²-4*2*(-2)=9+16=25=5²
х1=(3+5)/4=2
х2=(3-5)/4=-0,5
+. - +
_____.____._____
-0,5 2
[-0,5;2]
Verified answer
2х²-3х-2≤02х²-3х-2=0
Д=9-4·2·(-2)=25
√Д=5
х1=2
х2=-0,5
2х²-3х-2=2(х-2)(х+0,5)
2(х-2)(х+0,5)≤0
+ - +
---------------i----------------i--------→-
-0,5 2
x∈[-0,5;2]