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YLOCHEK98
@YLOCHEK98
July 2022
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решите неравенство: (2x+3)(2-x)>3
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Sveta57rus
4х-2х^2+6-3x>3
2x^2-x-3<0
Д=1+24=25
x1=3|2
x2=-1
xЭ(Э наоборот)(-1,3/2)
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Answers & Comments
2x^2-x-3<0
Д=1+24=25
x1=3|2
x2=-1
xЭ(Э наоборот)(-1,3/2)