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July 2022
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Решите неравенство (2x+3)(x-4)<x^2+4x-12
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sangers1959
Verified answer
2x²-4x+3x-12<x²+4x-12
x²-5x<0
x(x-5)<0
x>0 x<0
x<5 x∈(0;5) x>5 x∉
Ответ: х∈(0;5).
2 votes
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Answers & Comments
Verified answer
2x²-4x+3x-12<x²+4x-12x²-5x<0
x(x-5)<0
x>0 x<0
x<5 x∈(0;5) x>5 x∉
Ответ: х∈(0;5).