Объяснение:
f(x)=3cos(x)+1,5x
f
′
(x)=−3sin(x)+1,5
(x)=0=>−3sin(x)+1,5=0<=>sin(x)=0,5=>x=
6
π
+2πk
x=
5π
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Объяснение:
f(x)=3cos(x)+1,5x
f
′
(x)=−3sin(x)+1,5
f
′
(x)=0=>−3sin(x)+1,5=0<=>sin(x)=0,5=>x=
6
π
+2πk
x=
6
5π
+2πk