РЕШИТЕ НЕРАВЕНСТВО (3х-1)^2

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(3x-1)²-4<0
(3x-1-2)(3x-1+2)<0
(3x-3)(3x+1)<0
x=1 x=-1/3
x∈(-1/3;1)

1 votes Thanks 2

SherlockGooge16 (3х-1)^2 <4
9x² - 6x + 1 < 4
9x² - 6x - 3 < 0
y = 9x² - 6x - 3, квадратичная функция
9x² - 6x - 3 = 0 / :3
3x² - 2x - 1 = 0
D = 4 +12 = 16, 16>0, 2 корня
x₁ = (2 + 4)/6 = 1
x₂ = (2 - 4)/6 = -1/3

3 votes Thanks 2

SherlockGooge16 ответ: (-1/3 ; 1)

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