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galinashaforos
@galinashaforos
July 2022
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Решите неравенство (3x-5)^2>=(5x-3)^2.
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evstifeeva07
9x²-30x+25≥25x²-30x+9
-16x²+16≥0
x²-1≤0
(x-1)*(x+1)≤0
x∈[-1; 1]
3 votes
Thanks 17
Xasanov1992
мне кажется от -беск до -1
sofyaburkova1
(от + бесконечности;1 здесь квадратная скобка
sofyaburkova1
неет все правильно)
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Answers & Comments
-16x²+16≥0
x²-1≤0
(x-1)*(x+1)≤0
x∈[-1; 1]