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nadiabakrova03
@nadiabakrova03
April 2021
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Решите неравенство:
(9x^2-4)(16-x^2)(2x^2+3)>0
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anassstass
(9x² - 4)(16 - x²)(2x² + 3) > 0
(9x² - 4) > 0
(3x - 2)(3x + 2) > 0
x = 2/3; -2/3
(16 - x²) > 0
(4 - x)(4 + x) > 0
x = 4; -4
(2x² + 3) > 0
D = 9 - 8 = 1
x1 = -3 - 1 / 4 = -1
x2 = -3 + 1 / 4 = -0,5
Ответ: (-бесконечность; -1) V (-0,5; +бесконечность)
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Answers & Comments
(9x² - 4) > 0
(3x - 2)(3x + 2) > 0
x = 2/3; -2/3
(16 - x²) > 0
(4 - x)(4 + x) > 0
x = 4; -4
(2x² + 3) > 0
D = 9 - 8 = 1
x1 = -3 - 1 / 4 = -1
x2 = -3 + 1 / 4 = -0,5
Ответ: (-бесконечность; -1) V (-0,5; +бесконечность)