Home
О нас
Products
Services
Регистрация
Войти
Поиск
uchenic4
@uchenic4
August 2022
1
10
Report
Решите неравенство: cos^(2)x-0,5sinx>1
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sedinalana
Verified answer
Cos²x-0,5sinx-1>0
1-sin²x-0,5sinx-1>0
sin²x+0,5sinx<0
sinx=a
a²+0,5a<0
a(a+0,5)<0
a=0 a=-0,5
-0,5<a<0
-0,5<sinx<0
-7π/6+2πn<x<-π+2πn,n∈z U -11π+2πn<x<2πn,n∈z
0 votes
Thanks 0
More Questions From This User
See All
uchenic4
July 2022 | 0 Ответы
zapisat v ionnom vide feno32mg
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Решите неравенство: cos^(2)x-0,5sinx>1..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
Cos²x-0,5sinx-1>01-sin²x-0,5sinx-1>0
sin²x+0,5sinx<0
sinx=a
a²+0,5a<0
a(a+0,5)<0
a=0 a=-0,5
-0,5<a<0
-0,5<sinx<0
-7π/6+2πn<x<-π+2πn,n∈z U -11π+2πn<x<2πn,n∈z