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islamesenov
@islamesenov
August 2022
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Решите неравенство f'(x)⩽0
f(x) = x^4 - 2 x^3 + 3
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DariosI
Verified answer
F'(x)=(
x^4 - 2 x^3 + 3)'
f'(x)=4x
³-2*3x²=4x³-6x²
4x³-6x²≤0
4x²(x-1.5)≤0
x≤1.5
x∈(-∞; 1.5]
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Answers & Comments
Verified answer
F'(x)=(x^4 - 2 x^3 + 3)'f'(x)=4x³-2*3x²=4x³-6x²
4x³-6x²≤0
4x²(x-1.5)≤0
x≤1.5
x∈(-∞; 1.5]