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Pavidlo9000
@Pavidlo9000
July 2022
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Решите неравенство:
f'(x)<0, если f(x)=-x³+3x²-4
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ShirokovP
Verified answer
F ' (x) = - 3x^2 + 6x
f ' (x) < 0
- 3x^2 + 6x < 0 /:(-3)
x^2 - 2x > 0
x (x - 2) > 0
+ - +
----------- 0 --------------- 2 -------------> x
x ∈ ( - ∞; 0 ) ∪(2; + ∞)
2 votes
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Answers & Comments
Verified answer
F ' (x) = - 3x^2 + 6xf ' (x) < 0
- 3x^2 + 6x < 0 /:(-3)
x^2 - 2x > 0
x (x - 2) > 0
+ - +
----------- 0 --------------- 2 -------------> x
x ∈ ( - ∞; 0 ) ∪(2; + ∞)