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Michelle1101
@Michelle1101
July 2022
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Решите неравенство (х-8)(х+2)>= 2х^2+6х+11. Найдите его наибольшее целое отрицательное решение
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ВикаВикторовна
Verified answer
Х²+2х-8х-16 ≥ 2х²+6х+11
х²+12х+27 ≤ 0
D = 144-108= 36
x₁ = -12-6 / 2 = -9
x₂ = -12+6 / 2 = -3
+ - +
-----------.------------.----------->x
-9 -3
x∈[-9; -3]
Наибольшее целое отрицательное х = -3
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Verified answer
Х²+2х-8х-16 ≥ 2х²+6х+11х²+12х+27 ≤ 0
D = 144-108= 36
x₁ = -12-6 / 2 = -9
x₂ = -12+6 / 2 = -3
+ - +
-----------.------------.----------->x
-9 -3
x∈[-9; -3]
Наибольшее целое отрицательное х = -3