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fencingepee
@fencingepee
October 2021
1
14
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Решите неравенство
х^2(2х + 1)(х - 3) ≥ 0
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Answers & Comments
zarema1905
X^2(2^2-6x+x-3)=0
x^2(2x^2-5x-3)=0
x^2=0
2x^2-5x-3=0
a=2; b=-5; с= -3.
D=b^2-4ac=25-4*2*(-3)=25+24=49
X1=
-b+sqrtD
=
5+7
=
12
= 3
2a 4 4
X2=
-b-sqrtD
=
5-7
=
-1
2a 4 2
2 votes
Thanks 2
fencingepee
Ну так это корни , а решение неравенства ?
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Answers & Comments
x^2(2x^2-5x-3)=0
x^2=0
2x^2-5x-3=0
a=2; b=-5; с= -3.
D=b^2-4ac=25-4*2*(-3)=25+24=49
X1= -b+sqrtD =5+7 = 12 = 3
2a 4 4
X2= -b-sqrtD = 5-7 = -1
2a 4 2