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klimenkol21
@klimenkol21
March 2022
1
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Решите неравенство:
lg²х < lg х⁵- 6
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sangers1959
Verified answer
Lg²x<lgx⁵-6 ОДЗ: x>0
lg²x-5*lgx+6<0
lg²x-5*lgx+6=0 D=1
lgx=3 x=10³x x=1000
lgx=2 x=10² x=100 ⇒
(x-100)*(x-1000)<0
-∞______+_____100_____-_____1000_____+_____+∞
Ответ: x∈(100;1000).
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Answers & Comments
Verified answer
Lg²x<lgx⁵-6 ОДЗ: x>0lg²x-5*lgx+6<0
lg²x-5*lgx+6=0 D=1
lgx=3 x=10³x x=1000
lgx=2 x=10² x=100 ⇒
(x-100)*(x-1000)<0
-∞______+_____100_____-_____1000_____+_____+∞
Ответ: x∈(100;1000).