Решите неравенство log0.5(2x^2+3x+1)

June 2022 1 11 Report

Решите неравенство log0.5(2x^2+3x+1)<= 2log0.5(x-1)

Answers & Comments

wejde

Verified answer

Log0,5(2x²+3x+1)≤2log0,5(x-1)
D(y): 2x²+3x+1>0, x-1>0, x>1
a-b+c=0 (2-3+1=0) →x=-1, x=-0,5
2(x+1)(x+0,5)>0
//////////////////// ////////////////
__________o____________o_________
-1 -0,5
Учитывая, что x>1 → x∈(1;+∞)

log0,5(2x²+3x+1)≤log0,5(x-1)²
т.к. основание логарима меньше единицы, то:
2x²+3x+1≥x²-2x+1
2x²-x²+3x+2x+1-1≥0
x²+5x≥0
x(x+5)≥0
//////////// //////////////
______.______._______
-5 0
x∈[-∞;-5]U[0;+∞)
Учитывая D(y): x∈(1;+∞)

Ответ: x∈(1;+∞)

0 votes Thanks 0

Answers & Comments

Verified answer

pomogite izmenit formu slov of course some body fat is desire as it able u

prosto rasshifrujte slovokazhdaya bukva russkogo alfavita zakodirovana trehznachny

stepen okisleniya h2mno7

pomogite s odnim nomerom vnesite mnozhitel pod znak kornya x koren v 4 stepe

nazovite centry zhelezorudnoj promyshlennosti v rossii

nado bylo zapastis na noch drovami eto sostavnoe imennoe skazuemoe

HELP!! Complete the second sentence using the word given so that it has a simila...

otgadajte slova 1 not guilty 8 bukv 2the decision of a court 7 bukv 2ya e

dayu 20 ballov help complete the second sentence using the word given so th

HELP!! Complete the second sentence using the word given so that it has a simila...

рекомендуемые вопросы

Helpful Links

Helpful Social