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Аргон0605
@Аргон0605
July 2022
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Решите неравенство методом интервалов (х-1)(х-3)>0
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ВикаВикторовна
Verified answer
(х-1)(х-3)>0
(х-1)(х-3)=0
х-1=0; х₁ = 1
х-3=0; х₂ = 3
+ - +
--------₀---------₀-------->x
1 3
x∈(-∞; 1)∪(3; ∞)
19 votes
Thanks 35
Dимасuk
Verified answer
(x - 1)(x - 3) > 0
Нули: x = 1; 3.
||||||||+|||||||||1 - 3||||||+||||||||||||||
---------------0---------------------------0--------------> x
Ответ: x ∈ (-∞; 1) U (3; +∞).
5 votes
Thanks 8
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Answers & Comments
Verified answer
(х-1)(х-3)>0(х-1)(х-3)=0
х-1=0; х₁ = 1
х-3=0; х₂ = 3
+ - +
--------₀---------₀-------->x
1 3
x∈(-∞; 1)∪(3; ∞)
Verified answer
(x - 1)(x - 3) > 0Нули: x = 1; 3.
||||||||+|||||||||1 - 3||||||+||||||||||||||
---------------0---------------------------0--------------> x
Ответ: x ∈ (-∞; 1) U (3; +∞).