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TUKKKK
@TUKKKK
August 2022
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Решите неравенство методом интервалов
(x+8)(x-4)≤0
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crazyden4ik2694
(x+8)(x-4)=<0
x^2+4x-32=0
D=b^2-4ac=16-4*(-32)=144
x1=(-4+12)/2=4
x2=(-4-12)/2=-8
Так как (x+8)(x-4)=<0 то, [-8;4]
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Answers & Comments
x^2+4x-32=0
D=b^2-4ac=16-4*(-32)=144
x1=(-4+12)/2=4
x2=(-4-12)/2=-8
Так как (x+8)(x-4)=<0 то, [-8;4]