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wastyk
@wastyk
August 2022
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Zinder00
x+4,2>0
x>-4,2
ОДЗ: x є (-4,2; +∞).
√(x+4,2)=t
t+1/t≥5/2
t+1/t-5/2≥0
2t+2/t-5≥0
2t^2-5t+2≥0
2t^2-5t+2=0
a=2 b=-5 c=2
D=b^2-4ac=25-16=9
a1=(-b-√D)/2a=(5-3)/4=0,5
a2=(-b+√D)/2a=(5+3)/4=2
a=0
x ∈ (-4,2;-3,95] U [-0,2;∞)
Ответ: (-4,2;-3,95] U [-0,2;∞).
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Answers & Comments
x+4,2>0
x>-4,2
ОДЗ: x є (-4,2; +∞).
√(x+4,2)=t
t+1/t≥5/2
t+1/t-5/2≥0
2t+2/t-5≥0
2t^2-5t+2≥0
2t^2-5t+2=0
a=2 b=-5 c=2
D=b^2-4ac=25-16=9
a1=(-b-√D)/2a=(5-3)/4=0,5
a2=(-b+√D)/2a=(5+3)/4=2
a=0
x ∈ (-4,2;-3,95] U [-0,2;∞)
Ответ: (-4,2;-3,95] U [-0,2;∞).