Решите неравенство (x+1)^2>4x
(x+1)^2>4x
x^2+1>4x
x^2-4x+1>0
x^2-4x+1=0
D=(-4)^2-4*1*1=16-4=12
x1,2=4+-12/2
x1=4+12/2=8
x2=4-12/2=-4
Ответ: 8; -4
(x+1)^2>4xx∈(-∞, 1)⋃(1, ∞)
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(x+1)^2>4x
x^2+1>4x
x^2-4x+1>0
x^2-4x+1=0
D=(-4)^2-4*1*1=16-4=12
x1,2=4+-12/2
x1=4+12/2=8
x2=4-12/2=-4
Ответ: 8; -4
(x+1)^2>4x
x∈(-∞, 1)⋃(1, ∞)