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Солнце12131415
@Солнце12131415
August 2022
2
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Решите неравенство:
x^2-3x+2<0
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Akula17
D=b^2-4ac=(-3)^2-4*1*2=1
√D=√1
x1=3 + - √1 / 2 = 3+1 / 2 = 2
x2=3-1 / 2 = 1
Ответ: x
∈(2;1)
22 votes
Thanks 40
pezzieeele
Х^2-3х+2<0 найду нули функции
у=х^2-3х+2 решаю уравнение
х
^2
-3х+2=0 D=b2-4ac
D=(-3)
^2-4*2=9-8=1>0
х1,2=3+-1/2
х1=3-1/2=2/2=1
х2=3+1/2=4/2=2
Ответ: (1;2)
16 votes
Thanks 22
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Answers & Comments
√D=√1
x1=3 + - √1 / 2 = 3+1 / 2 = 2
x2=3-1 / 2 = 1
Ответ: x∈(2;1)
у=х^2-3х+2 решаю уравнение
х^2-3х+2=0 D=b2-4ac
D=(-3)^2-4*2=9-8=1>0
х1,2=3+-1/2
х1=3-1/2=2/2=1
х2=3+1/2=4/2=2
Ответ: (1;2)