Решите неравенство x^2-4x-5

September 2021 2 11 Report

Решите неравенство
x^2-4x-5<0

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Х² - 4х - 5< 0

х² - 4х - 5 = 0
D = (-4)² - 4 · 1 · (-5) = 16 + 20 = 36; √36 = 6
x₁ = (4 + 6)/2 = 5
x₂ = (4 - 6)/2 = -1

(x - 5)(x + 1) < 0
+ - +
______|_______|_______
-1 5
x ∈ (-1; 5)

1 votes Thanks 2

Alex85787857 Спасибо

tatyankagolman x^2-4x-5<0
a=1; b=-4; c=-5
D=b^2-4ac
D=16-4×1×(-5)=16-20
D=4
x1,2=-b+-√D/2a
x1=4-√4/2=4+2/2=6/2=3
x2=4-√4/2=4-2/2=2/2=1
Выражения имеет два корня.

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