Решите неравенство(0,5)^{-7x+12} \geq 32. Created by Лерка6666. algebra-ru

Решите неравенство(0,5)^{-7x+12} \geq 32...

Лерка6666 @Лерка6666

July 2022 1 3 Report

Решите неравенство
(0,5)^{-7x+12} \geq 32

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$(0,5)^{-7x+12} \geq 32\\\\0,5=\frac{5}{10}=\frac{1}{2}=2^{-1},\; \; 32=2^5\\\\2^{7x-12}\geq 2^5\\\\7x-12\geq 5\\7x\geq 17\\x\geq \frac{17}{7},\; x\geq 2\frac{3}{7}$

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