решите неравенство:
1) (x + 1)(x - 2)(x + 5) > 0;
2) x(x - 3)(x + 2) < 0.
1) (x + 1)(x - 2)(x + 5) > 0;
2) x(x - 3)(x + 2) < 0.
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Ответ:
1) ( -5<x^x<-1)v(2<x^x< "тут знак безеонечности поставь"
2) ( - "знак безеонечности" <x^x<-2)v(0<x^x<3)