решите неравенствоlog3(x2+7x-5)>1. Created by AnnaFoxx. matematika-ru

решите неравенствоlog3(x2+7x-5)>1...

AnnaFoxx @AnnaFoxx

August 2022 1 5 Report

решите неравенство
log3(x2+7x-5)>1

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eugeke

Verified answer

$log_3(x^2+7x-5)>1$
$x^2+7x-5>3$
$x^2+7x-8>0$
$D=49+32=81; \sqrt{D}=9$

$x_{1/2}= \frac{-7 \pm9}{2}=1; -8$

Ответ: $x\in(-\infty; -8) (1;+ \infty)$

ОДЗ:
$x^2+7x-5>0$
$D=49+20=69; \sqrt{D}= \sqrt{69} \approx8,3$

$x_{1/2} \frac{-7\pm8.3}{2} \approx0.65; -7,65$

5 votes Thanks 3

eugeke Надо бы сказать, что ОДЗ = (-00;-7,65)U(0,65;+00)

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AnnaFoxx August 2022 | 0 Ответы

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