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Sk1pperr
@Sk1pperr
August 2022
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решите неравентсво f'(x)больше 0
f(x)=-3xкубе+2xквадрат
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Verified answer
F(x)=-3x³+2x² f `(x)>0
f `(x)=-3*3x²+2*2x=-9x²+4x
-9x²+4x>0
9x²-4x <0
9x(x-4/9)<0
+ - +
_____________0________________4/9______________
x∈(0;4/9)
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Verified answer
F(x)=-3x³+2x² f `(x)>0f `(x)=-3*3x²+2*2x=-9x²+4x
-9x²+4x>0
9x²-4x <0
9x(x-4/9)<0
+ - +
_____________0________________4/9______________
x∈(0;4/9)