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kudryavtsevaan
@kudryavtsevaan
July 2022
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Решите неровность (х-4)(х+7)
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andreevnaelina
(х-4)(х+7)=0
х²+7х-4х-28=0
х²+3х-28=0
а=1; б=3; с= -28
D=б²-4ас=9-4×1×(-28)=9+112=121=11²
х1= -б+корень из D /2a= (-3+11) /2×1=8/2=4
x2= -б-корень из D/2a=(-3-11)/2=-14/2=-7
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Answers & Comments
х²+7х-4х-28=0
х²+3х-28=0
а=1; б=3; с= -28
D=б²-4ас=9-4×1×(-28)=9+112=121=11²
х1= -б+корень из D /2a= (-3+11) /2×1=8/2=4
x2= -б-корень из D/2a=(-3-11)/2=-14/2=-7