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Артур998
@Артур998
September 2021
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Решите номер 2.Есть вложение.
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DarkChemist
Fe + H2SO4 = FeSO4 + H2
n(Fe) = 14 / 56 = 0,25 (моль)
n(H2SO4) = 49 / 98 = 0,5 (моль)
m(FeSO4) = 0,25 * 152 =
38 (г)
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Answers & Comments
n(Fe) = 14 / 56 = 0,25 (моль)
n(H2SO4) = 49 / 98 = 0,5 (моль)
m(FeSO4) = 0,25 * 152 = 38 (г)