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Артур998
@Артур998
October 2021
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Решите номер 3.Есть вложение.
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oganesbagoyan
Verified answer
3)
2cos(2x -π/4) = 1 ;
cos(2x -π/4) = 1/2 ;
2x -π/4 = ±π/3 +2πk , k∈Z ;
2x = π/4 ±π/3 +2πk , k∈Z ;
x = π/8 ±π/6 +πk , k∈Z .
или иначе
x = -π/24 + πk ; x = 7π/24 + πk , k∈Z .
1 votes
Thanks 1
oganesbagoyan
Не нужно ! Функция " cos определена везде , т.е. x ∈(- ∞; +∞)
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Answers & Comments
Verified answer
3)2cos(2x -π/4) = 1 ;
cos(2x -π/4) = 1/2 ;
2x -π/4 = ±π/3 +2πk , k∈Z ;
2x = π/4 ±π/3 +2πk , k∈Z ;
x = π/8 ±π/6 +πk , k∈Z .
или иначе
x = -π/24 + πk ; x = 7π/24 + πk , k∈Z .