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Азяка21
@Азяка21
June 2022
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РЕШИТЕ ПЛИЗ!
4(4x−20)^2−19(4x−20)+12=0
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Ayreliya
4(16х²-160х+400)-76х+380+12=0
64х²-640х+1600-76х+392=0
64х²-716х+1992=0
Сокращаем на 4, получается
16х²-179х+498=0
Д=13²
х1=179+13/32=6
х2=179-13/32=5,1875
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Answers & Comments
64х²-640х+1600-76х+392=0
64х²-716х+1992=0
Сокращаем на 4, получается
16х²-179х+498=0
Д=13²
х1=179+13/32=6
х2=179-13/32=5,1875